Half-Life of Reaction
\[t_{1/2}=\frac{\ln(2)}{k}\]

Variables

t12[t½]reaction half-life (s)
kfirst-order rate constant (s⁻¹)

Description

What is this formula?


The half-life of a reaction is the time required for the concentration of a reactant to decrease to one-half of its initial value.


For first-order reactions, the half-life is constant and depends only on the rate constant.


When to use it


Use this formula when analyzing first-order reactions, radioactive decay, pharmaceutical degradation, and many natural exponential decay processes.


Example


Given:


k = 0.035 s^-1


Formula:


t½ = ln(2)/k


Substitution:


t½ = 0.693/0.035


Result:


t½ = 19.8 s


After 19.8 seconds, the reactant concentration will have decreased to one-half of its original value.


Applications


Chemical kinetics

Radioactive decay

Pharmaceutical stability

Environmental chemistry

Reaction engineering


Note


This formula applies specifically to first-order kinetics. Unlike first-order reactions, the half-life of zero-order and second-order reactions depends on the initial concentration and therefore changes as the reaction proceeds.


Because of its simplicity and broad applicability, the first-order half-life is the most commonly reported half-life in chemistry, pharmacology, and nuclear science.

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