Caloria-gramo
Caloria-gramo
\[\begin{aligned}
y[Joule] &= 4.184x[gram\text{-}calorie] \\
y[Kilojoule] &= 0.004184x \\
y[Kilocalorie] &= 0.001x \\
y[Watt\ hour] &= 0.00116222x \\
y[Kilowatt\ hour] &= 1.1622 \times 10^{-6}x \\
y[Electronvolt] &= 2.611 \times 10^{19}x \\
y[British\ thermal\ unit] &= 0.00396567x \\
y[US\ therm] &= 3.9666 \times 10^{-8}x \\
y[foot\ pound] &= 3.08596x
\end{aligned}\]
Variables
y = Variable dependiente
x = Variable independiente
Description
Descarga la aplicación fCalc para calcular esta fórmula y miles más:
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