Formula library

Concentration Cell Potential

Concentration Cell Potential
\[E=\frac{RT}{nF}\ln\left(\frac{C_2}{C_1}\right)\]

Variables

Econcentration cell potential (V)
Rgas constant (8.314 J·mol⁻¹·K⁻¹)
Tabsolute temperature (K)
nnumber of electrons transferred
FFaraday constant (96485 C/mol)
C2higher ion concentration
C1lower ion concentration

Description

What is this formula?


A concentration cell generates electrical potential solely because of a difference in ion concentration between two half-cells containing the same electrode material.


Unlike ordinary galvanic cells, no difference in electrode composition is required.


When to use it


Use this formula when calculating the voltage generated by concentration differences in electrochemical systems.


Example


Given:


C2 = 1.00 mol/L


C1 = 0.010 mol/L


T = 298 K


n = 2


R = 8.314 J·mol^-1·K^-1


F = 96485 C/mol


Formula:


E = (RT/nF)ln(C2/C1)


Substitution:


E = ((8.314×298)/(2×96485))ln(1.00/0.010)


Result:


E ≈ 0.059 V


The concentration difference generates a potential of approximately 59 mV.


Applications


Electrochemistry

Electrochemical sensors

Corrosion studies

Membrane systems

Battery science

Analytical chemistry


Note


This equation is a special case of the Nernst equation.


Because both electrodes are chemically identical, the standard cell potential is zero:


E° = 0


The entire cell voltage arises from the concentration gradient.


As the concentrations become equal:


C2 = C1


the logarithmic term becomes zero and the cell potential disappears.


Concentration cells provide a direct demonstration of how chemical potential differences can be converted into electrical energy.

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